If l1, l2, l3 are the lengths of the emitter, base and collector of a transistor, then

Question

If l1, l2, l3 are the lengths of the emitter, base and collector of a transistor, then (A) l1=l1=l3 (B) l2< l2 > l1 (C) l3 < l1 < l2 (D) l3>l1>l2

Tardigrade Admin · Accepted Answer

As collector is meant for collecting all the moving charge carriers, the collection process involves dissipation of heat from the charge carriers. In order to dissipate the heat, Collector is made with LARGE SURFACE AREA, which makes collector the larger than base and emitter.
Base is meant for passing the charge carrier from emitter to collector involving no special activities, hence its the smallest region Hence,

1_{3} > 1_{1} > 1_{2}

Q. If $l_{1}, l_{2}, l_{3}$ are the lengths of the emitter, base and collector of a transistor, then

$l_{1} = l_{1} = l_{3}$

$l_{2} < l_{2} > l_{1}$

$l_{3} < l_{1} < l_{2}$

$l_{3} > l_{1} > l_{2}$

Q. If l1​,l2​,l3​ are the lengths of the emitter, base and collector of a transistor, then

l1​=l1​=l3​

l2​<l2​>l1​

l3​<l1​<l2​

l3​>l1​>l2​

Q. If $l_{1}, l_{2}, l_{3}$ are the lengths of the emitter, base and collector of a transistor, then

$l_{1} = l_{1} = l_{3}$

$l_{2} < l_{2} > l_{1}$

$l_{3} < l_{1} < l_{2}$

$l_{3} > l_{1} > l_{2}$