If Ki and Kf are the initial and final values of kinetic energy of a body respectively, then the work done by the net force on the body is equal to

Question

If Ki and Kf are the initial and final values of kinetic energy of a body respectively, then the work done by the net force on the body is equal to (A) (Kf Ki/Kf-Ki) (B) Kf+Ki (C) (Kf+Ki/2) (D) Kf-Ki

Tardigrade Admin · Accepted Answer

According to work-energy theorem W=Kf-Ki

Q. If $K_{i}$ and $K_{f}$ are the initial and final values of kinetic energy of a body respectively, then the work done by the net force on the body is equal to

$\frac{K _{f} K _{i}}{K _{f} - K _{i}}$

$K_{f} + K_{i}$

$\frac{K _{f} + K _{i}}{2}$

$K_{f} - K_{i}$

According to work-energy theorem
$W = K_{f} - K_{i}$

Q. If Ki​ and Kf​ are the initial and final values of kinetic energy of a body respectively, then the work done by the net force on the body is equal to

Kf​−Ki​Kf​Ki​​

Kf​+Ki​

2Kf​+Ki​​

Kf​−Ki​