Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If ∫ (3x+1/(x-3)(x-5))dx = ∫(-5/(x-3))dx+∫ (B/(x-5))dx, then the value of B is
Q. If
∫
(
x
−
3
)
(
x
−
5
)
3
x
+
1
d
x
=
∫
(
x
−
3
)
−
5
d
x
+
∫
(
x
−
5
)
B
d
x
,
then the value of
B
is
2709
240
VITEEE
VITEEE 2018
Report Error
A
3
B
4
C
6
D
8
Solution:
We have,
(
x
−
3
)
(
x
−
5
)
3
x
+
1
=
x
−
3
−
5
+
x
−
5
B
3
x
+
1
=
−
5
(
x
−
5
)
+
B
(
x
−
3
)
Put
x
=
5
3
(
5
)
+
1
=
B
(
5
−
3
)
16
=
2
B
or
B
=
8