If initial concentration is doubled, the time for half reaction is also doubled, the order of reaction is

Question

If initial concentration is doubled, the time for half reaction is also doubled, the order of reaction is (A) zero (B) first (C) second (D) third

Tardigrade Admin · Accepted Answer

t1/2 propto (1/(cone, of reactant)n-1)For zero order, n = 0 The half life period propto (cone, of reactant).In the question, the time for half reaction is doubled when initial concentration is doubled it is zero order reaction.

Q. If initial concentration is doubled, the time for half reaction is also doubled, the order of reaction is

zero

first

second

third

$t_{1/2} \propto \frac{1}{( co n e , o f re a c t an t ) ^{n - 1}}$ For zero order, n = 0 The half life period $\propto$ (cone, of reactant).In the question, the time for half reaction is doubled when initial concentration is doubled it is zero order reaction.

Q. If initial concentration is doubled, the time for half reaction is also doubled, the order of reaction is

zero

first

second

third

t1/2​∝(cone,ofreactant)n−11​For zero order, n = 0 The half life period ∝ (cone, of reactant).In the question, the time for half reaction is doubled when initial concentration is doubled it is zero order reaction.

$t_{1/2} \propto \frac{1}{( co n e , o f re a c t an t ) ^{n - 1}}$ For zero order, n = 0 The half life period $\propto$ (cone, of reactant).In the question, the time for half reaction is doubled when initial concentration is doubled it is zero order reaction.