If in the reaction N2O42NO2-;x is that part of N2O4 which dissociates, then the number of molecules at equilibrium will be

Question

If in the reaction N2O42NO2-;x is that part of N2O4 which dissociates, then the number of molecules at equilibrium will be (A) 1 (B) 3 (C)  (1+x)  (D)  (1+x)2

Tardigrade Admin · Accepted Answer

N2O22NO2 1 0 before dissociation 1-x 2x after dissociation Total number of moles at equilibrium =1-x text +2x=1+ text x

Q. If in the reaction $N_{2} O_{4} 2 N O_{2}^{-}; x$ is that part of $N_{2} O_{4}$ which dissociates, then the number of molecules at equilibrium will be

1

3

$(1 + x)$

$(1 + x)^{2}$

$N_{2} O_{2} 2 N O_{2}$ 1 0 before dissociation $1 - x$ $2 x$ after dissociation Total number of moles at equilibrium $= 1 - x + 2 x = 1 + x$

Q. If in the reaction N2​O4​2NO2−​;x is that part of N2​O4​ which dissociates, then the number of molecules at equilibrium will be

1

3

(1+x)

(1+x)2

N2​O2​2NO2​ 1 0 before dissociation 1−x 2x after dissociation Total number of moles at equilibrium =1−x+2x=1+x

Q. If in the reaction $N_{2} O_{4} 2 N O_{2}^{-}; x$ is that part of $N_{2} O_{4}$ which dissociates, then the number of molecules at equilibrium will be

$(1 + x)$

$(1 + x)^{2}$

$N_{2} O_{2} 2 N O_{2}$ 1 0 before dissociation $1 - x$ $2 x$ after dissociation Total number of moles at equilibrium $= 1 - x + 2 x = 1 + x$