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Q. If in the reaction $ {{N}_{2}}{{O}_{4}}2NO_{2}^{-};x $ is that part of $ {{N}_{2}}{{O}_{4}} $ which dissociates, then the number of molecules at equilibrium will be

MGIMS WardhaMGIMS Wardha 2014

Solution:

$ {{N}_{2}}{{O}_{2}}2N{{O}_{2}} $ 1 0 before dissociation $ 1-x $ $ 2x $ after dissociation Total number of moles at equilibrium $ =1-x\text{ }+2x=1+\text{ }x $