If in the reaction N2O4 = 2NO2, α is that part of N2O4 which dissociates, then the number of moles at equilibrium will be

Question

If in the reaction N2O4 = 2NO2, α is that part of N2O4 which dissociates, then the number of moles at equilibrium will be (A) 3 (B) 1 (C) (1-α)2 (D) (1-α)

Tardigrade Admin · Accepted Answer

underset overset1(1-α) N2O4 leftharpoons underset overset02α 2NO2 Total mole at equilibrium = (1- α) + 2α =1+α

Q. If in the reaction $N_{2} O_{4} = 2 N O_{2}$ , $α$ is that part of $N_{2} O_{4}$ which dissociates, then the number of moles at equilibrium will be

$3$

$1$

$(1 - α)^{2}$

$(1 - α)$

$(1 - α) 1 N_{2} O_{4} ⇌ 2 α 0 2 N O_{2}$
Total mole at equilibrium $= (1 - α) + 2 α = 1 + α$

Q. If in the reaction N2​O4​=2NO2​, α is that part of N2​O4​ which dissociates, then the number of moles at equilibrium will be

3

1

(1−α)2

(1−α)

(1−α)1​N2​O4​​⇌2α02NO2​​ Total mole at equilibrium =(1−α)+2α=1+α

Q. If in the reaction $N_{2} O_{4} = 2 N O_{2}$ , $α$ is that part of $N_{2} O_{4}$ which dissociates, then the number of moles at equilibrium will be

$3$

$1$

$(1 - α)^{2}$

$(1 - α)$

$(1 - α) 1 N_{2} O_{4} ⇌ 2 α 0 2 N O_{2}$
Total mole at equilibrium $= (1 - α) + 2 α = 1 + α$