Question

If in hybrid orbital s-orbital character increases, then bond angle:

• A. increases
• B. decreases
• C. zero
• D. does not change

Answer 1

Answer: (A)

In a hybrid orbital, $s$-character increases bond angle increases.
e.g., Bond angle of, $s{p}^3<s{p}^2<sp$
$25\%33\%50\%s$-character