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Tardigrade
Question
Mathematics
If in a progression a1,a2,a3, ... etc. (ar=ar+1) bears a constant ratio with ar.ar+1, then the terms of the progression are in
Q. If in a progression
a
1
,
a
2
,
a
3
,
...
etc.
(
a
r
=
a
r
+
1
)
bears a constant ratio with
a
r
.
a
r
+
1
,
then the terms of the progression are in
1810
184
Sequences and Series
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A
A.P.
17%
B
G.P.
20%
C
H.P.
60%
D
none of these.
3%
Solution:
Since
a
r
.
a
r
+
1
a
r
−
a
r
+
1
constant for all
r
⇒
a
r
+
1
1
−
a
r
1
=
constant for all
r
⇒
a
1
,
a
2
,
a
3
,
.....
are in
H
.
P
.