If in a parallelogram ABDC, the coordinates of A, B and C are respectively (1, 2), (3, 4) and (2, 5), then the equation of the diagonal AD is :

Question

If in a parallelogram ABDC, the coordinates of A, B and C are respectively (1, 2), (3, 4) and (2, 5), then the equation of the diagonal AD is : (A) 5x + 3y - 11 = 0 (B) 3x - 5y + 7 = 0 (C) 3x + 5y - 13 = 0 (D) 5x - 3y + 1 = 0

Tardigrade Admin · Accepted Answer

co-ordinates of point D are (4,7) ⇒ line AD is 5x - 3y + 1 = 0

Q. If in a parallelogram $A B D C$ , the coordinates of $A, B$ and $C$ are respectively $(1, 2), (3, 4)$ and $(2, 5),$ then the equation of the diagonal $A D$ is :

5x + 3y - 11 = 0

3x - 5y + 7 = 0

3x + 5y - 13 = 0

5x - 3y + 1 = 0

co-ordinates of point $D$ are $(4, 7)$
$\Rightarrow$ line $A D$ is $5 x - 3 y + 1 = 0$

Q. If in a parallelogram ABDC, the coordinates of A,B and C are respectively (1,2),(3,4) and (2,5), then the equation of the diagonal AD is :