If in a nuclear fusion reaction, mass defect is 0.3 %, then energy released in fusion of 1 kg mass

Question

If in a nuclear fusion reaction, mass defect is 0.3 %, then energy released in fusion of 1 kg mass (A) 27 ×1010 J (B) 27 ×1011 J (C) 27 ×1012 J (D) 27 ×1013 J

Tardigrade Admin · Accepted Answer

Here, Δ m=0.3 % of 1 kg =(0.3/100)kg=3×10-3 kg ∴ E=(Δ m)c2=3×10-3×(3×108)2 =27×1013 J

Q. If in a nuclear fusion reaction, mass defect is $0.3%$ , then energy released in fusion of $1 k g$ mass

$27 \times 1 0^{10} J$

$27 \times 1 0^{11} J$

$27 \times 1 0^{12} J$

$27 \times 1 0^{13} J$

Here, $Δ m = 0.3%$ of $1 k g$
$= \frac{0.3}{100} k g = 3 \times 1 0^{- 3} k g$
$∴ E = (Δ m) c^{2} = 3 \times 1 0^{- 3} \times (3 \times 1 0^{8})^{2}$
$= 27 \times 1 0^{13} J$

Q. If in a nuclear fusion reaction, mass defect is 0.3%, then energy released in fusion of 1kg mass

27×1010J

27×1011J

27×1012J

27×1013J