Question

If in a nuclear fusion reaction, mass defect is $0.3\%$, then energy released in fusion of $1 \,kg$ mass

• A. $27 \times10^{10}\,J$
• B. $27 \times10^{11}\,J$
• C. $27 \times10^{12}\,J$
• D. $27 \times10^{13}\,J$

Answer 1

Answer: (D)

Here, $\Delta m=0.3\%$ of $1\,kg$
$=\frac{0.3}{100}kg=3\times10^{-3}\, kg$
$\therefore E=\left(\Delta m\right)c^{2}=3\times10^{-3}\times\left(3\times10^{8}\right)^{2}$
$=27\times10^{13}\,J$