Question

If in a diode valve, the plate potential becomes double, then plate current will be:

• A. $2\sqrt{2}$ times
• B. 8 times
• C. $3\sqrt{3}$ times
• D. 2 times

Answer 1

Answer: (A)

The Child's equation is
$I_P\propto V_p^{3/2}$
$\therefore I_p^{\prime }={\left(\frac{V_p^{\prime }}{V_p}\right)}^{3/2}{I}_p$
or $I_p=(2{)}^{3/2}{I}_p$
$=2\sqrt{2}{I}_p$