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Physics
If in a diode valve, the plate potential becomes double, then plate current will be:
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Q. If in a diode valve, the plate potential becomes double, then plate current will be:
Rajasthan PMT
Rajasthan PMT 2004
Semiconductor Electronics: Materials Devices and Simple Circuits
A
$ 2\sqrt{2} $ times
33%
B
8 times
6%
C
$ 3\sqrt{3} $ times
22%
D
2 times
39%
Solution:
The Child's equation is
$I_{P} \propto V_{p}^{3 / 2}$
$\therefore I_{p}'=\left(\frac{V_{p}'}{V_{p}}\right)^{3 / 2} I_{p} $
or $I_{p} =(2)^{3 / 2} I_{p} $
$=2 \sqrt{2} I_{p} $