Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If In=∫ limits0(π/4) tan n x d x where n is positive integer then I10+I8 is equal to
Q. If
I
n
=
0
∫
4
π
tan
n
x
d
x
where
n
is positive integer then
I
10
+
I
8
is equal to
2046
192
KCET
KCET 2021
Integrals
Report Error
A
9
16%
B
7
1
26%
C
8
1
32%
D
9
1
24%
Solution:
I
n
+
I
n
−
2
=
n
−
1
1