Question

If $I,m,n$ are in arithmetic progression, then the straight line $lx+my+n=0$ will pass through the point

• A. (-1, 2)
• B. (1,-2)
• C. (1, 2)
• D. (2, 1)

Answer 1

Answer: (B)

The equation of given line is $1x+my+n=\mathrm{0...}(1)$
If $1,m,n$ are in arithmetic progression then, $2m=1+n...(2)$
Equation (2) can be written as,
$1-2m+n=\mathrm{0...}s(3)$
Now comparing the equation (3) with equation (1),
we can clearly see that line $1x+$ my $+n=0$
passes through the point $(1,-2)$