If I1=∫ limits01 2x2 d x, I2=∫ limits01 2x3 d x I3=∫ limits12 2x2 d x and I4=∫ limits12 2x3 d x then -

Question

If I1=∫ limits01 2x2 d x, I2=∫ limits01 2x3 d x I3=∫ limits12 2x2 d x and I4=∫ limits12 2x3 d x then - (A) I3 >I4 (B) I 3= I 4 (C) I 1 > I 2 (D) I 2 > I 1

Tardigrade Admin · Accepted Answer

Correct answer is (c) I 1 > I 2

Q. If $I_{1} = 0 \int 1 2^{x^{2}} d x, I_{2} = 0 \int 1 2^{x^{3}} d x I_{3} = 1 \int 2 2^{x^{2}} d x$ and $I_{4} = 1 \int 2 2^{x^{3}} d x$ then -

$I_{3} > I_{4}$

$I_{3} = I_{4}$

$I_{1} > I_{2}$

$I_{2} > I_{1}$

Correct answer is (c) $I_{1} > I_{2}$

Q. If I1​=0∫1​2x2dx,I2​=0∫1​2x3dxI3​=1∫2​2x2dx and I4​=1∫2​2x3dx then -

I3​>I4​

I3​=I4​

I1​>I2​

I2​>I1​

Correct answer is (c) I1​>I2​

Q. If $I_{1} = 0 \int 1 2^{x^{2}} d x, I_{2} = 0 \int 1 2^{x^{3}} d x I_{3} = 1 \int 2 2^{x^{2}} d x$ and $I_{4} = 1 \int 2 2^{x^{3}} d x$ then -

$I_{3} > I_{4}$

$I_{3} = I_{4}$

$I_{1} > I_{2}$

$I_{2} > I_{1}$

Correct answer is (c) $I_{1} > I_{2}$