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Q. If $I_1=\int\limits_0^1 2^{x^2} d x, I_2=\int\limits_0^1 2^{x^3} d x I_3=\int\limits_1^2 2^{x^2} d x$ and $I_4=\int\limits_1^2 2^{x^3} d x$ then -

Integrals

Solution:

Correct answer is (c) $I _1 > I _2$