If I1 and I2 be the size of the images respectively for the two positions of lens in the displacement method, then the size of the object is given by

Question

If I1 and I2 be the size of the images respectively for the two positions of lens in the displacement method, then the size of the object is given by (A)  (I1/I2) (B)  I× I2 (C)  √I1× I2 (D)  √(I1/I2)

Tardigrade Admin · Accepted Answer

(I1/O)=(v/u) ⇒ (I2/O) =(u/v) ∴ O2 =I1 I2 O=√I1 × I2

Q. If $I_{1}$ and $I_{2}$ be the size of the images respectively for the two positions of lens in the displacement method, then the size of the object is given by

$\frac{I _{1}}{I _{2}}$

$I \times I_{2}$

$I_{1} \times I_{2}$

$\frac{I _{1}}{I _{2}}$

$\frac{I _{1}}{O} = \frac{v}{u}$
$\Rightarrow \frac{I _{2}}{O} = \frac{u}{v}$
$∴ O^{2} = I_{1} I_{2}$
$O = I_{1} \times I_{2}$

Q. If I1​ and I2​ be the size of the images respectively for the two positions of lens in the displacement method, then the size of the object is given by

I2​I1​​

I×I2​

I1​×I2​​

I2​I1​​​

OI1​​=uv​ ⇒OI2​​=vu​ ∴O2=I1​I2​ O=I1​×I2​​

Q. If $I_{1}$ and $I_{2}$ be the size of the images respectively for the two positions of lens in the displacement method, then the size of the object is given by

$\frac{I _{1}}{I _{2}}$

$I \times I_{2}$

$I_{1} \times I_{2}$

$\frac{I _{1}}{I _{2}}$

$\frac{I _{1}}{O} = \frac{v}{u}$
$\Rightarrow \frac{I _{2}}{O} = \frac{u}{v}$
$∴ O^{2} = I_{1} I_{2}$
$O = I_{1} \times I_{2}$