Question

If $I_{1}$ and $I_{2}$ be the size of the images respectively for the two positions of lens in the displacement method, then the size of the object is given by

• A. $ \frac{I_{1}}{I_{2}}$
• B. $ I\times I_{2}$
• C. $ \sqrt{I_{1}\times I_{2}}$
• D. $ \sqrt{\frac{I_{1}}{I_{2}}}$

Answer 1

Answer: (C)

$\frac{I_{1}}{O}=\frac{v}{u}$
$\Rightarrow \frac{I_{2}}{O} =\frac{u}{v}$
$\therefore O^{2} =I_{1} I_{2}$
$O=\sqrt{I_{1} \times I_{2}}$