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Tardigrade
Question
Chemistry
If for an ideal gas, the ratio of pressure and volume is constant and is equal to 1 atm L -1, the molar heat capacity at constant pressure would be
Q. If for an ideal gas, the ratio of pressure and volume is constant and is equal to
1
a
t
m
L
−
1
,
the molar heat capacity at constant pressure would be
1510
191
Thermodynamics
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A
2
3
R
B
2
R
C
2
5
R
D
zero
Solution:
By definition
H
=
E
+
P
V
(
d
T
d
H
)
P
=
(
d
T
d
E
)
P
+
+
P
(
d
T
d
V
)
P
=
C
p
,
m
For the given ideal gas, we will have
P
V
=
RT
or
V
2
=
RT
or
2
V
(
d
T
d
V
)
P
=
R
or
(
d
T
d
V
)
P
=
2
V
R
E
=
2
3
RT
or
(
d
T
d
E
)
P
=
2
3
R
=
C
v
,
m
C
p
,
m
=
2
3
R
+
P
×
2
V
R
=
(
2
3
+
2
1
)
R
=
2
R