If for 2A2B(g) leftharpoons 2A2(g) + B2(g), Kp = Total Pressure (at equilibrium) and starting the dissociation from 4 mol of A2B then

Question

If for 2A2B(g) leftharpoons 2A2(g) + B2(g), Kp = Total Pressure (at equilibrium) and starting the dissociation from 4 mol of A2B then (A) degree of dissociation of A2B will be (2/3) (B) total no. of moles at equilibrium will be (14/3) (C) at equilibrium the no. of moles of A2B is not equal to the no. of moles of B2 (D) at equilibrium the no. of moles of A2B is equal to the no. of moles of A2

Tardigrade Admin · Accepted Answer

Correct answer is (a) degree of dissociation of A2B will be (2/3)

Q. If for $2 A_{2} B (g) ⇌ 2 A_{2} (g) + B_{2} (g),$
$K_{p} =$ Total Pressure (at equilibrium) and starting the dissociation from $4$ mol of $A_{2} B$ then

degree of dissociation of $A_{2} B$ will be $(2/3)$

total no. of moles at equilibrium will be $(14/3)$

at equilibrium the no. of moles of $A_{2} B$ is not equal to the no. of moles of $B_{2}$

at equilibrium the no. of moles of $A_{2} B$ is equal to the no. of moles of $A_{2}$

Correct answer is (a) degree of dissociation of $A_{2} B$ will be $(2/3)$

Q. If for 2A2​B(g)⇌2A2​(g)+B2​(g), Kp​= Total Pressure (at equilibrium) and starting the dissociation from 4 mol of A2​B then

degree of dissociation of A2​B will be (2/3)

total no. of moles at equilibrium will be (14/3)

at equilibrium the no. of moles of A2​B is not equal to the no. of moles of B2​

at equilibrium the no. of moles of A2​B is equal to the no. of moles of A2​