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Mathematics
If f(x)=| x -3 2 x2-18 3 x3-81 x -5 2 x2-50 4 x3-500 1 2 3| then f(1) f(3)+f(3) f(5)+f(5) f(1) is equal to
Q. If
f
(
x
)
=
∣
∣
x
−
3
x
−
5
1
2
x
2
−
18
2
x
2
−
50
2
3
x
3
−
81
4
x
3
−
500
3
∣
∣
then
f
(
1
)
f
(
3
)
+
f
(
3
)
f
(
5
)
+
f
(
5
)
f
(
1
)
is equal to
1970
206
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A
f
(
1
)
B
f
(
3
)
C
f
(
1
)
+
f
(
3
)
D
f
(
1
)
+
f
(
5
)
Solution:
f
(
x
)
=
(
x
−
3
)
(
x
−
5
)
∣
∣
1
1
1
2
(
x
+
3
)
2
(
x
+
5
)
2
3
(
x
2
+
9
+
3
x
)
4
(
x
2
+
25
+
5
x
)
3
∣
∣
⇒
f
(
3
)
=
f
(
5
)
=
0
So,
f
(
1
)
f
(
3
)
+
f
(
3
)
⋅
f
(
5
)
+
f
(
5
)
f
(
1
)
=
0
=
f
(
3
)