Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If f(x)=x3-(1/x3), then f(x)+f((1/x)) is equal to
Q. If
f
(
x
)
=
x
3
−
x
3
1
, then
f
(
x
)
+
f
(
x
1
)
is equal to
1741
235
Relations and Functions
Report Error
A
2
x
3
18%
B
2
x
3
1
29%
C
0
42%
D
1
10%
Solution:
Since
f
(
x
)
=
x
3
−
x
3
1
;
f
(
x
1
)
=
x
3
1
−
x
3
1
1
=
x
3
1
−
x
3
Hence,
f
(
x
)
+
f
(
x
1
)
=
x
3
−
x
3
1
+
x
3
1
−
x
3
=
0