Question

If $f(x)=\mathrm{Min}.\left\{x+6,|x+e+1|,e^{-x}\right\}$, then maximum value of $f(x)$ is

• A. $\frac{e+5}{2}$
• B. $2e$
• C. $e$
• D. $\frac{7+e}{2}$

Answer 1

Answer: (C)

Correct answer is (c) $e$