If f(x) = ln((x2 +e/x2 +1)), then range of f(x) is

Question

If f(x) = ln((x2 +e/x2 +1)), then range of f(x) is (A) (0, 1) (B) (0, 1] (C) [0, 1) (D) 0, 1

Tardigrade Admin · Accepted Answer

f(x) = ln((x2 +e/x2 +1)) = ln((x2+1-1+e/x2+1)) = ln(1+(e-1/x2+1)) Clearly range is (0, 1]

Q. If $f (x) = l n (\frac{x ^{2} + e}{x ^{2} + 1})$ , then range of f(x) is