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Question
Mathematics
If f ( x ) is a function which is both odd and even simultaneously then f (1)+ f (2) is equal to
Q. If
f
(
x
)
is a function which is both odd and even simultaneously then
f
(
1
)
+
f
(
2
)
is equal to
302
119
Relations and Functions - Part 2
Report Error
A
0
B
1
C
2
D
3
Solution:
Θ
f
(
x
)
is both even as well as odd
∴
f
(
x
)
=
0
∴
f
(
1
)
+
f
(
2
)
=
0