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Question
Mathematics
If f(x)=| textCos x 1 0 0 2 cos x 3 0 1 2 cos x| then displaystyle lim x arrow π f(x)=
Q. If
f
(
x
)
=
∣
∣
Cos
x
0
0
1
2
cos
x
1
0
3
2
cos
x
∣
∣
then
x
→
π
lim
f
(
x
)
=
2279
177
KCET
KCET 2021
Determinants
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A
−
1
36%
B
1
27%
C
0
31%
D
3
7%
Solution:
f
(
x
)
=
4
cos
3
x
−
3
cos
x
=
cos
3
x
x
→
π
lim
cos
3
x
=
cos
3
π
=
−
1