If f(x) be a continuous function defined for 1≤ x≤ 3,f(x)∈ Q,∀ x∈ [1 , 3],f(2)=10 , then the value of f(1 . 8) is (where Q is a set of all rational numbers).

Question

If f(x) be a continuous function defined for 1≤ x≤ 3,f(x)∈ Q,∀ x∈ [1 , 3],f(2)=10 , then the value of f(1 . 8) is (where Q is a set of all rational numbers). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

∴ f(x)∈ Q=f(x) is constant function ∴ f(2)=10 ⇒ f(1.8)=10

Q. If $f (x)$ be a continuous function defined for $1 \leq x \leq 3, f (x) \in Q, \forall x \in [1, 3], f (2) = 10$ , then the value of $f (1.8)$ is
(where $Q$ is a set of all rational numbers).

$∴ f (x) \in Q = f (x)$ is constant function
$∴ f (2) = 10$
$\Rightarrow f (1.8) = 10$

Q. If f(x) be a continuous function defined for 1≤x≤3,f(x)∈Q,∀x∈[1,3],f(2)=10 , then the value of f(1.8) is (where Q is a set of all rational numbers).

∴f(x)∈Q=f(x) is constant function ∴f(2)=10 ⇒f(1.8)=10

Q. If $f (x)$ be a continuous function defined for $1 \leq x \leq 3, f (x) \in Q, \forall x \in [1, 3], f (2) = 10$ , then the value of $f (1.8)$ is
(where $Q$ is a set of all rational numbers).

$∴ f (x) \in Q = f (x)$ is constant function
$∴ f (2) = 10$
$\Rightarrow f (1.8) = 10$