If f (x) = 3x4 - 5x2 + 9, then value of f (x - 1) is

Question

If f (x) = 3x4 - 5x2 + 9, then value of f (x - 1) is (A) 3x4 + 12x3 + 13x2 + 2x + 7 (B) 3x4 - 12x3 - 13x2 - 2x - 7 (C) 3x4 - 12x3 + 13x2 - 2x + 7 (D) 3x4 - 12x3 - 13x2 + 2x + 7

Tardigrade Admin · Accepted Answer

We have, f (x) = 3x4 - 5x2 + 9 ∴ f (x - 1) = 3 (x - 1)4 - 5 (x - 1)2 + 9 = 3x4 - 12x3 + 13x2 - 2x + 7

Q. If $f (x) = 3 x^{4} - 5 x^{2} + 9$ , then value of $f (x - 1)$ is

$3 x^{4} + 12 x^{3} + 13 x^{2} + 2 x + 7$

$3 x^{4} - 12 x^{3} - 13 x^{2} - 2 x - 7$

$3 x^{4} - 12 x^{3} + 13 x^{2} - 2 x + 7$

$3 x^{4} - 12 x^{3} - 13 x^{2} + 2 x + 7$

We have,
$f (x) = 3 x^{4} - 5 x^{2} + 9$
$∴ f (x - 1) = 3 (x - 1)^{4} - 5 (x - 1)^{2} + 9$
$= 3 x^{4} - 12 x^{3} + 13 x^{2} - 2 x + 7$

Q. If f(x)=3x4−5x2+9, then value of f(x−1) is

3x4+12x3+13x2+2x+7

3x4−12x3−13x2−2x−7

3x4−12x3+13x2−2x+7

3x4−12x3−13x2+2x+7