Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If f: R arrow R , f(x) = 3x - 2 then (fof)(x) + 2 =
Q. If
f
:
R
→
R
,
f
(
x
)
=
3
x
−
2
then
(
f
o
f
)
(
x
)
+
2
=
1793
183
Relations and Functions - Part 2
Report Error
A
f
(
x
)
15%
B
2
f
(
x
)
32%
C
3
f
(
x
)
40%
D
−
f
(
x
)
12%
Solution:
(
f
o
f
)
(
x
)
+
2
=
f
(
f
(
x
))
+
2
=
3
(
3
x
−
2
)
−
2
+
2
=
3
f
(
x
)