Question

If $f_0$ and $f_e$ are the focal lengths of the objective and eye-piece respectively of a telescope, then its magnifying power will be

• A. $f_0+f_e$
• B. $f_0\times f_e$
• C. $f_0/f_e$
• D. $\frac{1}{2}(f_0+f_e)$

Answer 1

Answer: (C)

Magnification of a telescope is given by $m=\frac{f_0}{f_e},$ where $f_0$ is the focal length of the objective lens and $f_e$ is the focal length of eye-piece.