If excess of AgNO3 solution is added to 100 mL of a 0.024 M solution of dichlorobis (ethylenediamine) cobalt (III) chloride, how many moles of AgCl be precipitated?

Question

If excess of AgNO3 solution is added to 100 mL of a 0.024 M solution of dichlorobis (ethylenediamine) cobalt (III) chloride, how many moles of AgCl be precipitated? (A) 0.0012 (B) 0.0016 (C) 0.0024 (D) 0.0048

Tardigrade Admin · Accepted Answer

Co3+ + 2Cl- + 2 (en) net charge = +1 [Co(en)2Cl2]+Cl- → [Co(en)2Cl2]+ + Cl- Only one Cl- which is precipitated as AgCl 100 mL of 0.024 M complex = 2.4 millimol = 0.0024 mol

Q. If excess of $A g N O_{3}$ solution is added to $100 m L$ of a $0.024 M$ solution of dichlorobis (ethylenediamine) cobalt (III) chloride, how many moles of $A g Cl$ be precipitated?

$0.0012$

$0.0016$

$0.0024$

$0.0048$

$C o^{3 +} + 2 C l^{-} + 2 (e n)$
net charge = $+ 1$
$[C o (e n)_{2} C l_{2}]^{+} C l^{-} \to [C o (e n)_{2} C l_{2}]^{+} + C l^{-}$
Only one $C l^{-}$ which is precipitated as $A g Cl$
$100 m L$ of $0.024 M$ complex = $2.4$ millimol = $0.0024$ mol

Q. If excess of AgNO3​ solution is added to 100mL of a 0.024M solution of dichlorobis (ethylenediamine) cobalt (III) chloride, how many moles of AgCl be precipitated?

0.0012

0.0016

0.0024

0.0048