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Question
Chemistry
If equilibrium constant of the reaction of weak acid HA with NaOH is 109, then pH of 0.1 M NaA is
Q. If equilibrium constant of the reaction of weak acid HA with
N
a
O
H
is
1
0
9
, then pH of
0.1
M
N
a
A
is
2978
228
Equilibrium
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A
5
14%
B
9
59%
C
7
17%
D
8
10%
Solution:
H
A
+
N
a
O
H
⇌
N
a
A
+
H
2
O
K
=
1
0
9
∴
For
N
a
A
+
H
2
O
⇌
N
a
O
H
+
H
A
;
K
=
1
0
−
9
Initial
At eqm
0.1
M
(
0.1
−
α
)
M
α
M
α
M
[
N
a
A
]
[
N
a
O
H
]
[
H
A
]
=
1
0
−
9
0.1
−
α
α
2
=
1
0
−
9
As
α
is very small,
0.1
−
α
=
0.1
α
2
=
1
0
−
9
×
0.1
α
=
1
0
−
5
[
O
H
−
]
=
[
N
a
O
H
]
=
1
0
−
5
M
P
H
=
14
−
pO
H
=
14
−
5
=
9