If enthalpy of atomisation for Br2(I) is x kJ/mol and bond enthalpy for Br2 is y kj/mol, the relation between them :

Question

If enthalpy of atomisation for Br2(I) is x kJ/mol and bond enthalpy for Br2 is y kj/mol, the relation between them : (A) is x < y (B) does not exist (C) is x > y (D) is x = y

Tardigrade Admin · Accepted Answer

Enthalpy of atomisation of Br2(l) Δ Hatoms=Δ Hvap+Δ HBE x=Δ Hvap+y so, x> y

Q. If enthalpy of atomisation for $B r_{2 (I)}$ is $x k J / m o l$ and bond enthalpy for $B r_{2}$ is $y kj / m o l$ , the relation between them :

is $x < y$

does not exist

is $x > y$

is $x = y$

Enthalpy of atomisation of $B r_{2} (l)$
$Δ H_{a t o m s} = Δ H_{v a p} + Δ H_{BE}$
$x = Δ H_{v a p} + y$
$so, x > y$

Q. If enthalpy of atomisation for Br2(I)​ is xkJ/mol and bond enthalpy for Br2​ is ykj/mol, the relation between them :

is x<y

does not exist

is x>y

is x=y

Enthalpy of atomisation of Br2​(l) ΔHatoms​=ΔHvap​+ΔHBE​ x=ΔHvap​+y so,x>y

Q. If enthalpy of atomisation for $B r_{2 (I)}$ is $x k J / m o l$ and bond enthalpy for $B r_{2}$ is $y kj / m o l$ , the relation between them :

is $x < y$

is $x > y$

is $x = y$

Enthalpy of atomisation of $B r_{2} (l)$
$Δ H_{a t o m s} = Δ H_{v a p} + Δ H_{BE}$
$x = Δ H_{v a p} + y$
$so, x > y$