If electric force F e and magnetic force F B are given as F e= qE and F B = qVB respectively then find out dimensions of E / B where E = Electric field V = Velocity B = Magnetic field q = Charge B = Magnetic q = Charge

Question

If electric force F e and magnetic force F B are given as F e= qE and F B = qVB respectively then find out dimensions of E / B where E = Electric field V = Velocity B = Magnetic field q = Charge B = Magnetic q = Charge (A) [ M 1 L 0 T -1] (B) [ M 0 L 0 T -1] (C) [ M 0 LT -1]. (D) [ M 1 L 1 T -1]

Tardigrade Admin · Accepted Answer

F e= qE F B = qVB [ qE ]=[ qVB ] [( F / B )]=[ V ]

Q. If electric force $F_{e}$ and magnetic force $F_{B}$ are given as
$F_{e} = qE$
and $F_{B} = q V B$ respectively then find out dimensions of $E / B$ where
$E =$ Electric field
$V =$ Velocity
$B =$ Magnetic field
$q =$ Charge
$B =$ Magnetic $q =$ Charge

$[M^{1} L^{0} T^{- 1}]$

$[M^{0} L^{0} T^{- 1}]$

$[M^{0} L T^{- 1]}$

$[M^{1} L^{1} T^{- 1}]$

$F_{e} = qE$
$F_{B} = q V B$
$[qE] = [q V B]$
$[\frac{F}{B}] = [V]$

Q. If electric force Fe​ and magnetic force FB​ are given as Fe​=qE and FB​=qVB respectively then find out dimensions of E/B where E= Electric field V= Velocity B= Magnetic field q= Charge B= Magnetic q= Charge

[M1L0T−1]

[M0L0T−1]

[M0LT−1]

[M1L1T−1]