If each resistance in the figure is of 9 Ω then reading of ammeter is:

Question

If each resistance in the figure is of 9 Ω then reading of ammeter is: (A) 5 A (B) 8 A (C) 2 A (D) 9 A

Tardigrade Admin · Accepted Answer

Total resistance of circuit (1/R)=(1/9)+ ldots 9 times ⇒ R=1 Ω i=(V/R)=(9/1)=9 amp Current in each resistance is 9 amp. Reading of ammeter =1+1+1+1+1=5 amp

Q. If each resistance in the figure is of $9 Ω$ then reading of ammeter is:

5 A

8 A

2 A

9 A

Total resistance of circuit
$\frac{1}{R} = \frac{1}{9} + \dots 9$ times
$\Rightarrow R = 1 Ω$
$i = \frac{V}{R} = \frac{9}{1} = 9 am p$
Current in each resistance is $9 am p$ .
Reading of ammeter
$= 1 + 1 + 1 + 1 + 1 = 5 am p$

Q. If each resistance in the figure is of 9Ω then reading of ammeter is:

5 A

8 A

2 A

9 A

Total resistance of circuit R1​=91​+…9 times ⇒R=1Ω i=RV​=19​=9amp Current in each resistance is 9amp. Reading of ammeter =1+1+1+1+1=5amp

Q. If each resistance in the figure is of $9 Ω$ then reading of ammeter is:

Total resistance of circuit
$\frac{1}{R} = \frac{1}{9} + \dots 9$ times
$\Rightarrow R = 1 Ω$
$i = \frac{V}{R} = \frac{9}{1} = 9 am p$
Current in each resistance is $9 am p$ .
Reading of ammeter
$= 1 + 1 + 1 + 1 + 1 = 5 am p$