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Q. If each resistance in the figure is of $9 \, \Omega $ then reading of ammeter is:Physics Question Image

Rajasthan PMTRajasthan PMT 2000Current Electricity

Solution:

Total resistance of circuit
$ \frac{1}{R}=\frac{1}{9}+\ldots 9 $ times
$\Rightarrow R=1\, \Omega $
$i=\frac{V}{R}=\frac{9}{1}=9 \,amp$
Current in each resistance is $9 \,amp$.
Reading of ammeter
$=1+1+1+1+1=5\, amp$