If Ep and Ek are the potential energy and kinetic energy of the electron in a stationary orbit in the hydrogen atom, the value of Ep/Ek is

Question

If Ep and Ek are the potential energy and kinetic energy of the electron in a stationary orbit in the hydrogen atom, the value of Ep/Ek is (A) -2 (B) 2 (C) -1 (D) 1

Tardigrade Admin · Accepted Answer

Here, Ep = - (1/4 π ∈0) (Ze2/r) and Ek = (1/8 π ∈0) (Ze2/r) ∴ (Ep/Ek) = - 2

Q. If $E_{p}$ and $E_{k}$ are the potential energy and kinetic energy of the electron in a stationary orbit in the hydrogen atom, the value of $E_{p} / E_{k}$ is

-2

2

-1

1

Here, $E_{p} = - \frac{1}{4 π \in _{0}} \frac{Z e ^{2}}{r}$ and $E_{k} = \frac{1}{8 π \in _{0}} \frac{Z e ^{2}}{r}$
$∴$ $\frac{E _{p}}{E _{k}} = - 2$

Q. If Ep​ and Ek​ are the potential energy and kinetic energy of the electron in a stationary orbit in the hydrogen atom, the value of Ep​/Ek​ is

-2

2

-1

1

Here, Ep​=−4π∈0​1​rZe2​ and Ek​=8π∈0​1​rZe2​ ∴ Ek​Ep​​=−2

Q. If $E_{p}$ and $E_{k}$ are the potential energy and kinetic energy of the electron in a stationary orbit in the hydrogen atom, the value of $E_{p} / E_{k}$ is

Here, $E_{p} = - \frac{1}{4 π \in _{0}} \frac{Z e ^{2}}{r}$ and $E_{k} = \frac{1}{8 π \in _{0}} \frac{Z e ^{2}}{r}$
$∴$ $\frac{E _{p}}{E _{k}} = - 2$