If Eo M++ / M=-1.2 V, Eo X /M-=-1.1 V and Eo O2 / H2 O=1.23 V, then on electrolysis of aqueous solution of salt M X, the products obtained are

Question

If Eo M++ / M=-1.2 V, Eo X /M-=-1.1 V and Eo O2 / H2 O=1.23 V, then on electrolysis of aqueous solution of salt M X, the products obtained are (A)  M,X2 (B) H2,X2 (C) H2,O2 (D)  M,O2

Tardigrade Admin · Accepted Answer

Given, Eo M+ / M=-1.2 V Eo x2 / x-=-1.1 V Eo O2 / H2 O=1.23 V On electrolysis of aqueous solution of salt MX. The products obtained depends on the given E o values i.e. cathodic reaction will be one with higher E o red value. Anodic reaction will be one with higher E o text oxi value or lower E o text red value. Hence, the products are H2 and X2.

Q. If $E^{o}_{M^{+}}^{+} / M = - 1.2 V, E^{o}_{X} / M^{-} = - 1.1 V$ and $E^{o}_{O_{2} / H_{2} O} = 1.23 V$ , then on electrolysis of aqueous solution of salt $MX$ , the products obtained are

$M, X_{2}$

$H_{2}, X_{2}$

$H_{2}, O_{2}$

$M, O_{2}$

Q. If EoM++​/M=−1.2V,EoX​/M−=−1.1V and EoO2​/H2​O​=1.23V, then on electrolysis of aqueous solution of salt MX, the products obtained are

M,X2​

H2​,X2​

H2​,O2​

M,O2​

Q. If $E^{o}_{M^{+}}^{+} / M = - 1.2 V, E^{o}_{X} / M^{-} = - 1.1 V$ and $E^{o}_{O_{2} / H_{2} O} = 1.23 V$ , then on electrolysis of aqueous solution of salt $MX$ , the products obtained are

$M, X_{2}$

$H_{2}, X_{2}$

$H_{2}, O_{2}$

$M, O_{2}$