If Ei is the ionization energy of H atom in ground state and R is Rydberg constant, then they are related as

Question

If Ei is the ionization energy of H atom in ground state and R is Rydberg constant, then they are related as (A) R = (Ei/hc) (B) R = (2 Ei/hc) (C) R = (hc/Ei c) (D) R = (hc/2 Ei )

Tardigrade Admin · Accepted Answer

As En = - (Rhc/n2) or E1 = - Rhc (For n=1) or R = - (Ei/hc) (∵ E1 = Ei )

Q. If $E_{i}$ is the ionization energy of $H$ atom in ground state and $R$ is Rydberg constant, then they are related as

$R = \frac{E _{i}}{h c}$

$R = \frac{2 E _{i}}{h c}$

$R = \frac{h c}{E _{i} c}$

$R = \frac{h c}{2 E _{i}}$

As $E_{n} = - \frac{R h c}{n ^{2}}$ or $E_{1} = - R h c$ (For $n = 1$ )
or $R = - \frac{E _{i}}{h c} (∵ E_{1} = E_{i})$

Q. If Ei​ is the ionization energy of H atom in ground state and R is Rydberg constant, then they are related as

R=hcEi​​

R=hc2Ei​​

R=Ei​chc​

R=2Ei​hc​

As En​=−n2Rhc​ or E1​=−Rhc (For n=1) or R=−hcEi​​(∵E1​=Ei​)