Question

If dissociation for reaction, $PC{l}_5\rightleftharpoons PC{l}_3+C{l}_2$, is $20\%$ at $1$ atm pressure. Calculate $K_c$.

• A. $0.04$
• B. $0.05\%$
• C. $0.07$
• D. $0.06$

Answer 1

Answer: (B)

$K_c=\frac{\left[PC{l}_3\right]\left[C{l}_2\right]}{\left[PC{l}_5\right]}=\frac{\left[\frac{20}{100}\right]\times \left[\frac{20}{1000}\right]}{\left[\frac{80}{100}\right]}$
$=\frac{0.2\times 0.2}{0.8}=\frac{0.04}{0.8}=0.05$