If dielectric constant of water is 81, then its permittivity is

Question

If dielectric constant of water is 81, then its permittivity is (A) 7.2 × 1010 ( C 2/ N - m 2) (B) 8.86 × 10-9 ( C 2/ N - m 2) (C) 1.02 × 10-12 ( C 2/ N - m 2) (D) None of these

Tardigrade Admin · Accepted Answer

Permittivity of water ε=ε0 K =8.85 × 10-12 × 81 =7.2 × 10-10 C2 / N- m 2

Q. If dielectric constant of water is $81$ , then its permittivity is

$7.2 \times 1 0^{10} \frac{C ^{2}}{N - m ^{2}}$

$8.86 \times 1 0^{- 9} \frac{C ^{2}}{N - m ^{2}}$

$1.02 \times 1 0^{- 12} \frac{C ^{2}}{N - m ^{2}}$

None of these

Permittivity of water $ε = ε_{0} K$
$= 8.85 \times 1 0^{- 12} \times 81$
$= 7.2 \times 1 0^{- 10} C^{2} / N - m^{2}$

Q. If dielectric constant of water is 81, then its permittivity is

7.2×1010N−m2C2​

8.86×10−9N−m2C2​

1.02×10−12N−m2C2​