Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If Δ=|-x&a&b b&-x&a a&b&-x|, then a factor of Δ is
Q. If
Δ
=
∣
∣
−
x
b
a
a
−
x
b
b
a
−
x
∣
∣
, then a factor of
Δ
is
1216
238
Determinants
Report Error
A
a
+
b
+
x
B
x
2
−
(
a
−
b
)
x
+
a
2
+
b
2
+
ab
C
x
2
+
(
a
+
b
)
x
+
a
2
+
b
2
−
ab
D
x
Solution:
Applying
C
1
→
C
1
+
C
2
+
C
3
we get
Δ
=
∣
∣
a
+
b
−
x
a
+
b
−
x
a
+
b
−
x
a
−
x
b
b
b
−
x
∣
∣
=
(
a
+
b
−
x
)
∣
∣
1
1
1
a
−
x
b
b
a
−
x
∣
∣
=
(
a
+
b
−
x
)
∣
∣
1
0
0
a
−
x
−
a
b
−
a
b
a
−
b
−
x
−
b
∣
∣
[using
R
2
→
R
2
−
R
1
and
R
3
→
R
3
−
R
1
]
=
(
a
+
b
−
x
)
[
(
x
+
a
)
(
x
+
b
)
+
(
a
−
b
)
2
]
[expanding along
C
1
]
=
(
a
+
b
−
x
)
[
x
2
+
(
a
+
b
)
x
+
a
2
+
b
2
−
ab
]