If Δ E is the heat of reaction for C2H5OH(l) + 3O2(g) - 2CO2(g) +3H2O(l) at constant volume, the Δ H (heat of reaction at constant pressure), at constant temperature is

Question

If Δ E is the heat of reaction for C2H5OH(l) + 3O2(g) -> 2CO2(g) +3H2O(l) at constant volume, the Δ H (heat of reaction at constant pressure), at constant temperature is (A)  Δ H=Δ E+RT  (B)  Δ H=Δ E-RT  (C)  Δ H=Δ E-2RT  (D)  Δ H=Δ E+2RT

Tardigrade Admin · Accepted Answer

We know that, Δ H=Δ E+Δ n R T where, Δ n= number of moles of gaseous products - number of moles of gaseous reactants =2-3=-1 So, Δ H=Δ E-R T

Q. If $Δ E$ is the heat of reaction for
$C X_{2} H X_{5} OH (l) + 3 O X_{2} X_{(g)} 2 CO X_{2} X_{(g)} + 3 H X_{2} O (l)$ at constant volume, the $Δ H$ (heat of reaction at constant pressure), at constant temperature is

$Δ H = Δ E + RT$

$Δ H = Δ E - RT$

$Δ H = Δ E - 2 RT$

$Δ H = Δ E + 2 RT$

We know that,

$Δ H = Δ E + Δ n RT$

where,

$Δ n =$ number of moles of gaseous products

- number of moles of gaseous reactants

$= 2 - 3 = - 1$

So, $Δ H = Δ E - RT$

Q. If ΔE is the heat of reaction for CX2​HX5​OH(l)+3OX2​X(g)​​​2COX2​X(g)​​+3HX2​O(l) at constant volume, the ΔH (heat of reaction at constant pressure), at constant temperature is

ΔH=ΔE+RT

ΔH=ΔE−RT

ΔH=ΔE−2RT

ΔH=ΔE+2RT