If [ Cu ( H 2 O )4]2+ absorbs a light of wavelength 600 nm for d - d transition, then the value of octahedral crystal field splitting energy for [ Cu ( H 2 O )6]2+ will be × 10-21J. (Nearest integer ) (Given: h=6.63 × 10-34 Js and c =3.08 × 108 ms -1 )

Question

If [ Cu ( H 2 O )4]2+ absorbs a light of wavelength 600 nm for d - d transition, then the value of octahedral crystal field splitting energy for [ Cu ( H 2 O )6]2+ will be × 10-21J. (Nearest integer ) (Given: h=6.63 × 10-34 Js and c =3.08 × 108 ms -1 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ t =( hc /λ)=(6.63 × 10-34 × 3.08 × 108/600 × 10-9) =(6.63 × 3.08 × 10-17/600) =0.034034 × 10-17 =340.34 × 10-21 J Δ0=(9/4) Δ t =(9/4) × 340.34 × 10-21 =765.765 × 10-21 J ≈ 766 × 10-21 J

Q. If [Cu(H2​O)4​]2+ absorbs a light of wavelength 600nm for d−d transition, then the value of octahedral crystal field splitting energy for [Cu(H2​O)6​]2+ will be ______×10−21J. (Nearest integer ) (Given : h=6.63×10−34Js and c=3.08×108ms−1 )

Δt​=λhc​=600×10−96.63×10−34×3.08×108​ =6006.63×3.08×10−17​ =0.034034×10−17 =340.34×10−21J Δ0​=49​Δt​ =49​×340.34×10−21 =765.765×10−21J ≈766×10−21J