Question

If $\cot (\theta -\alpha ),3\cot \theta ,\cot (\theta +\alpha )$ are in A.P. and $\theta$ is not an integral multiple of $\frac{\pi }{2}$, then $\frac{2{\sin }^2\theta }{{\sin }^2\alpha }$ is equal to

Answer 1

Answer: 2

Correct answer is (b)