Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If | cos θ -1 1 cos 2 θ 4 3 2 7 7|=0 then the number of values of θ in [0, 2 π]
Q. If
∣
∣
cos
θ
cos
2
θ
2
−
1
4
7
1
3
7
∣
∣
=
0
then the number of values of
θ
in
[
0
,
2
π
]
1816
228
Report Error
A
1
19%
B
2
56%
C
3
8%
D
4
17%
Solution:
cos
θ
=
8
−
1
±
65
Hence number of solutions
=
2