Question

If cos 3x + sin $\left(2x-\frac{7\pi }{6}\right)=-2,$then x is equal to

• A. $\frac{\pi }{3}(6k+1)$
• B. $\frac{\pi }{3}(6k-1)$
• C. $\frac{\pi }{3}(2k+1)$
• D. none of these.

Answer 1

Answer: (A)

Correct answer is (a) $\frac{\pi }{3}(6k+1)$