Question

If $C{l}_2$ is passed through hot aqueous $NaOH$, the products formed have $Cl$ in different oxidation states. These are indicated as

• A. -1 and +1
• B. -1 and +5
• C. +1 and +5
• D. -1 and +3

Answer 1

Answer: (B)

If $C{l}_2$ is passed through hot aqueous $NaOH$, it results in the formation of sodium chloride and sodium chlorate as
$\underset{\text{Hot}}{6NaOH}+3C{l}_2⟶5NaCl+NaCl{O}_3+3H_{2}O$
In $NaCl$, let oxidation state of $Cl$ be $x$.
$+1+x=0$ or $x=-1$
In $NaCl{O}_3$, let oxidation state of $Cl$ be $Y.$
$+1+y+\left(r^2\right)3=0$
$y-5=0$
$\therefore y=+5$
Thus, the obtained compounds have $Cl$ in $-1$ and $+5$ oxidation states.